python tool: open note if only one match
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parent
5181d573a6
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@ -7,12 +7,12 @@ import sys
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import time
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import time
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def listnotes(filter = ""):
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def listnotes(filter = ""):
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cnt = 0
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matching = []
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for i in reversed(range(len(data))):
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for i in reversed(range(len(data))):
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if filter in data[i]["title"]:
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if filter in data[i]["title"]:
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print("[" + str(i) + "]", data[i]["title"])
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print("[" + str(i) + "]", data[i]["title"])
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cnt += 1
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matching.append(data[i])
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return cnt
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return matching
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def readtextfile(path):
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def readtextfile(path):
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with io.open(path, mode = "r", encoding = "utf-8") as f:
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with io.open(path, mode = "r", encoding = "utf-8") as f:
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@ -100,7 +100,8 @@ while not (command == "quit" or command == "exit" or command == "q"):
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elif note:
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elif note:
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editnote(note)
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editnote(note)
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else:
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else:
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if listnotes(command) == 0:
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matching = listnotes(command)
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if len(matching) == 0:
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if ask("create '" + command + "'? "):
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if ask("create '" + command + "'? "):
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note = {
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note = {
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"title": command,
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"title": command,
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@ -108,5 +109,7 @@ while not (command == "quit" or command == "exit" or command == "q"):
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}
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}
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data.insert(0, note)
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data.insert(0, note)
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editnote(note)
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editnote(note)
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elif len(matching) == 1:
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editnote(matching.pop())
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command = input("> ")
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command = input("> ")
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